9a^2+3a-2=0

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Solution for 9a^2+3a-2=0 equation: 



9a^2+3a-2=0

a = 9; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·9·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*9}=\frac{-12}{18}
=-2/3
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*9}=\frac{6}{18}
=1/3
$

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